Why does `Integral(a, b)` w.r.t. `IndexedBase(c)[d]` give `Integral(0, b)` and not just `0`?

351

January 25, 2017, at 00:07 AM

When I integrate sympy.Integral(a, b) with regard to c[d], i.e. with regard to IndexedBase(c)[d], I get Integral(0, b) which is clearly just 0, as .doit() will show. Why is it shown as Integral(0, b) rather than 0?

In [416]: (sympy.Integral(a, b)).diff(sympy.IndexedBase(c)[d])
Out[416]: 
⌠     
⎮ 0 db
⌡

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