namedtuple TypeError count of positional arguments
63
February 06, 2019, at 00:10 AM
Why does the TypeError message indicate 3 positional arguments if the namedtuple only calls for two? Why does it say that 4 were given?
from collections import namedtuple
Transition = namedtuple('Transition', ('one', 'two'))
a = Transition(1,2,3)
#TypeError: __new__() takes 3 positional arguments but 4 were given
Answer 1
The first argument on an instance method is always the instance itself (usually named self. Calling Transition(1,2) is Transition.__new__(self, 1, 2).
*Edit: thanks @Slam for pointing out that namedtuple used __new__ instead of __init__
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