continue loop after socket error

I'm using a python loop for finding open ports. The way it should work is if a port from my list is open and accepting a tcp connection, it will send me a response and if not it will skip to the next port number.

The problem I'm having is if the first port isn't responding, I receive an error from socket and the loop stops. Here's the script including how my ports list is defined.

import numpy;
import socket;
import sys;
with open("ports.ls") as f:
    ports = f.read().split(",");
portslist = []
for i in ports:
    portslist.append(i.strip());
portslist = [int(i) for i in portslist]
for i in portslist:
    target_host = sys.argv[1];
    target_port = i;
    print "[*] port:%d" % target_port;
    client = socket.socket(socket.AF_INET, socket.SOCK_STREAM);
    client.connect((target_host, i));
    client.send("GET / HTTP/1.1\r\nHost: %s\r\n\r\n" % target_host);
    response = client.recv(4096);
    print response;

and the error I get is

socket.error: [Errno 11] Resource temporarily unavailable

How do I continue the loop to the next iteration despite the first port not being responsive?