Javascript sort an array of strings that containing numbers

var collator = new Intl.Collator(undefined, {numeric: true, sensitivity: 'base'});
var myArray = ['1_Document', '11_Document', '2_Document'];
console.log(myArray.sort(collator.compare));

I believe your issue lies in how you are using hasNumber. If you are using it as a conditional, it will always be truthy. A function in JavaScript is always truthy, which means your first condition will always be met and will never hit your else block.

I think you are looking to see if any elements in the array can be converted to a number. In this case, you need to inspect the array in its entirety. This is what Array#some or Array#every are designed for. Depending on your requirements, you can either:

1. Check if every element in the array can be converted to a number or
2. Check if at least one element can be converted.

In either situation, you are inspecting a single string at any point in time. I believe hasNumber should be renamed isNumber, for clarity's sake.

const isNumber = (myString) => /\d/.test(myString);};
// ...
const hasNumber = filter.every(str => isNumber(str)) // if every element the array can be converted to a number
if (hasNumber) {

You can branch inside the the callback to the Array.sort:

1-if the elements contain numeric values then sort according to those values

2-else sort according to Alphabetic order

function sortAlphaNumeric(arr) {
    return arr.sort((first,second) => {
        let re = /\d+/;
        if(re.test(first) && re.test(second)){
            return parseInt(first.match(re) - parseInt(second.match(re)))
        }
        else{
            return first.codePointAt(0) - second.codePointAt(0) 
        }
    })
}
console.log(sortAlphaNumeric(["12W", "60W", "25W"]))
console.log(sortAlphaNumeric(["IP67", "IP68", "IP20"]))
console.log(sortAlphaNumeric(["White", "Red", "Black"]))
console.log(sortAlphaNumeric(["100cm", "10cm", "50cm"]))
console.log(sortAlphaNumeric(["3000°K", "2700°K", "2000°K"]))